Physics, asked by deviit, 1 year ago

A car accelerates from 36 km/h to 90 km/h in 5 s on a straight rod . What was its acceleration in m/s^2 and how far did it travel in this time ? Assume constant acceleration and direction of motion remains constant .​

Answers

Answered by milanmilankumar1995
12

Answer:

ans. 3m/s^2

Explanation:

first convert 36 km/h into m/s by multiplying by 1000 and divide by 60*60 it comes 10m/s and simmilarly to 90km/h then it comes 25m/s. substract 10m/s from 25m/s i.e. (25m/s - 10m/s) and devide it by given time i.e. by 5s then ans. come (25-10)/5 = 3m/s^2

is it correct ..

Answered by ashutoshdhawan493
8

Answer:

3 m/s^2

Explanation:

t=5 s

difference in speed =90-36=54 km/h

now we convert 54 km/h in m/s so here we multiply it by 5/18

so it comes 54*5/18=15 m/s

now acceleration =difference in speed/time

                             =15/5

                             =3 m/s^2

s=ut+1/2at^2

s=1/2*3*(5)^2

s=1/2*25*3

s=1/2*75

s=37.5 m

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