a car accelerates from 36km to 54km in 10 seconds find its acceleration and distance travelled by car
Answers
Answered by
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HOLA!!!
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HERE YOUR ANSWER IS
GIVEN
Initial velocity (u) = 36km /hr= 36×1000/60×60
= 36000/3600 = 10ms^-1
Final velocity (v) = 54km/hr = 54000/3600
= 15ms^-1
Time (t) = ?
SOLUTION
Accleration = (v-u)/t
=( 15 -10) /10
Acceleration = 5/10 = 1/2 = 0.5ms^-2
we know a kinematical equation
s = ut+1/2at^2
= (10)(10)+1/2 (0.5)(10)^2
= 100 + 1/2 (0.5)(100)
= 100 + 1/2 (50)
= 100 + 25
s = 125m
Therefore distance = 125m
__________________
HOPE IT HELPS YOU :D
_________
HERE YOUR ANSWER IS
GIVEN
Initial velocity (u) = 36km /hr= 36×1000/60×60
= 36000/3600 = 10ms^-1
Final velocity (v) = 54km/hr = 54000/3600
= 15ms^-1
Time (t) = ?
SOLUTION
Accleration = (v-u)/t
=( 15 -10) /10
Acceleration = 5/10 = 1/2 = 0.5ms^-2
we know a kinematical equation
s = ut+1/2at^2
= (10)(10)+1/2 (0.5)(10)^2
= 100 + 1/2 (0.5)(100)
= 100 + 1/2 (50)
= 100 + 25
s = 125m
Therefore distance = 125m
__________________
HOPE IT HELPS YOU :D
Saviturchauhan:
hey u there is calculation mistake when u were finding acceleration plz check
in que it's mentioned to find acceleration
there is calculation mistake here (15-10)/10=1/5
how 5/10 is 1/5 for u? always 5/10 = 1/2
tq by the way ...I too did a small mistake in answer...anyhow I'm thanking you for helping me rectify the ans
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0
hey u here ur answer
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