Math, asked by train81, 11 months ago

a car accelerates from 5 metre per second square to 20 metre per second square in 10 second calculate the acceleration and the distance covered by the car in that time​

Answers

Answered by praneethks
1

Answer:

v= final velocity =20 m/s.

u=initial velocity =5 m/s.

v=u+at=>20=5+a(10)=>(20-5)/10=a =>a=1.5 m/s2. Acceleration is 1.5 metre per second square.

 {v}^{2} -  {u}^{2}  = 2as =  >  {20}^{2} -  {5}^{2} =

2(1.5)s =  > 375 = 3s =  > s =  \frac{375}{3} =

125. Distance covered by the car in 10 seconds is 125 metres. Hope it helps you.

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