Question

a car accelerates from 5 metre per second square to 20 metre per second square in 10 second calculate the acceleration and the distance covered by the car in that time​

Answer 1

Answer:

v= final velocity =20 m/s.

u=initial velocity =5 m/s.

v=u+at=>20=5+a(10)=>(20-5)/10=a =>a=1.5 m/s2. Acceleration is 1.5 metre per second square.

${v}^{2} - {u}^{2} = 2as = > {20}^{2} - {5}^{2} =$

$2(1.5)s = > 375 = 3s = > s = \frac{375}{3} =$

125. Distance covered by the car in 10 seconds is 125 metres. Hope it helps you.