Question

A car accelerates from 6 m/s to 16 m/s in 10 s .calucalte the acceleration and the distance

Answer 1

For the car;

initial velocity (u) = 6 m/s

final velocity (v) = 16 m/s

time elapsed (t) = 10 s

acceleration of the car (a)

$= \frac{v - u}{t} \\ = \frac{16 - 6}{10} = \frac{10}{10} \\ = 1 \: m {s}^{ - 2}$

a = 1 m/s²

displacement of the car (s), using third

kinematical equation;

$= ut + \frac{1}{2} a {t}^{2} \\ = (6)(10) + ( \frac{1}{2} )(1) {(10)}^{2} \\ = 60 + \frac{1}{2} \times 100 \\ = 60 + 50 \\ = 110 \: m$

s = 110 m

Hence, acceleration of the car is 1 m/s² and distance travelled by it is 110 m