Question

A car accelerates from 6 m/s to 16 m/s in 10s calculate the distance covered by the car in that time?​

Answer 1

Answer:

110 m

Explanation:

u = 6 m / s

v = 16 m / s

t = 10 s

a = ( v - u ) / t

= ( 16 m / s - 6 m / s ) / 10 s

= 10 m / s / 10 s

= 1 m / s²

S = ut + ½ at²

= 6 m / s × 10 s + ½ × 1 m / s² × ( 10 s )²

= 60 m + ½ × 1 m / s² × 100 s²

= 60 m + 50 m

= 110 m

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Answer 2

Initial velocity = u

u=6m/s

Final velocity = v

v=16m/s

Time=t=10s

⋅Acceleration=a

a=(v−u)/t

=(16−6)/10

=1m/s

2

⋅Distance=s

From the newton's second law,

s=

2a

(v

2

−u

2

)

​

s=

(2×1)

(256−36)

​

=110m