a car accelerates from 6 metre per second to 16 m per second in10 seconds calculate the acceleration and the distance covered by the car in that time
Answers
Answered by
12
v=u+at
16=6+a*10
a=(16-6)/10
a=6/10=3/5 m/s^2
Again s=ut+1/2a(t)^2
=6*10+1/2*3/5*(10)^2
=60+3/5*100
=60+60
=120 m
16=6+a*10
a=(16-6)/10
a=6/10=3/5 m/s^2
Again s=ut+1/2a(t)^2
=6*10+1/2*3/5*(10)^2
=60+3/5*100
=60+60
=120 m
Answered by
8
u=6m/s
v=16m/s
t=10s
a=v-u/t
=(16-6)/10m/s square
=10/10m/s square
=1m/s square
hope this will help u... please now help me... in my question.
v=16m/s
t=10s
a=v-u/t
=(16-6)/10m/s square
=10/10m/s square
=1m/s square
hope this will help u... please now help me... in my question.
tomudi:
u can find distance by ur self after this by putting the value or equation
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