A car accelerates from 6 metre per second to 16 metre per second in 10 seconds calculate the acceleration and the distance covered by the car in that time
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acceleration = v - u / t
= 16 - 6 / 10
= 10/ 10 = 1 m/s
using 3rd eqn. Of motion
s = v^2 - u^2 / 2a
Putting the values:
s = 16^2 - 6^2 / 10
s = 256 - 36 / 10
s = 220 / 10
s = 22 m
22m is your answer
= 16 - 6 / 10
= 10/ 10 = 1 m/s
using 3rd eqn. Of motion
s = v^2 - u^2 / 2a
Putting the values:
s = 16^2 - 6^2 / 10
s = 256 - 36 / 10
s = 220 / 10
s = 22 m
22m is your answer
How 2a=10 ?
It's 2×1=2
220÷2=110m.
Your answer is wrong.
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