Question

A car accelerates from 6 ms–1 16 ms–1 in 10 sec. Calculate (a) the acceleration and (b) the distance covered by the car in that time.

Answer 1

v= 16m/s
u= 6m/s
t=10s
v=u+at
16= 6+a×10
16-6= a*10
10/10=a
1 =a
s=ut+1/2at^2
s= 6×10×1/2×1×10^2
s= 60+ 1/2×100
s= 60+50
s= 110m

Answer 2

u = 6m/s

v = 16m/s

t = 10s.

a = v-u/t

a  = 16-6/10

= 10/10

a = 1m/s²

distance =?=s

We know that,

2as = v²-u²

2(1)(s) = (16)²-(6)²

2s = 256-36

2s = 220

s = 110