Question

A car accelerates from 6 ms 16 ms'in 10 sec. Calculate the distance covered by the car in that time.​

Answer 1

Explanation:

ATQ, a car accelerates from 6m/s to 16m/s in 10 seconds.

initial velocity = v = 6m/s

final velocity = u = 16m/s

total time taken = t = 10 seconds

acceleration = a = ?

➡ distance = s = ?

(a) using first equation of motion

➡ v = u + at

➡ 16m/s = 6m/s + 10a

➡ 16 - 6 = 10a

➡ 10m/s = 10a

➡ a = 10/10

➡ a = 1m/s²

hence, the acceleration of the car is 1m/s²

(b) now we can use two equation of motion 2nd and 3rd. answer will be same..

let's find the distance using both equations.

➡ s = ut + 1/2 at²

= (6 × 10) + 1/2 × 1 × 10²

= 60 + 1/2 × 100

= 60 + 50

= 110m

using 3rd equation

➡ 2as = v² - u² (here we don't need t = time)

➡ 2 × 1 × s = 16² - 6²

➡ 2s = 256 - 36

➡ s = 220/2

➡ s = 110m

hence, the distance covered by the car is 110m.

Answer 2

Explanation:

so the answer is on the picture