a car accelerates from 6m|s to 16 m|s in 10sec.calculate the acceleration and distance covered by the car in that time
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Answered by
3
acceleration = v - u/t
u = 6 m/s
v = 16 m/s
t = 10 sec
a = 16 - 6/10
a = 10/10
a = 1 m/s^2
Now,
s = ut + 1/2 at^2
s = 6 x 10 + 1/2 1 x 10 x 10
s = 60 +50
s = 110 m
Hence, distance is 110 m.
Hope this helps.
u = 6 m/s
v = 16 m/s
t = 10 sec
a = 16 - 6/10
a = 10/10
a = 1 m/s^2
Now,
s = ut + 1/2 at^2
s = 6 x 10 + 1/2 1 x 10 x 10
s = 60 +50
s = 110 m
Hence, distance is 110 m.
Hope this helps.
Answered by
1
acceleration=v-u/t
a=(16-6)/10
a=1m/s^2
s=ut+1/2at2
=6*10+1/2*1*10^2
s=110m
a=(16-6)/10
a=1m/s^2
s=ut+1/2at2
=6*10+1/2*1*10^2
s=110m
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