Physics, asked by ash09954, 11 months ago

A car accelerates from 6m/s to 16m/s. Calculate the acceleration and the distance covered by the car in that time.

Answers

Answered by gumpahari123
5

V=u+at

16=6+a*10

a=(16-6)/10

a=6/10=3/5 m/s^2

Again s=ut+1/2a(t)^2

=6*10+1/2*3/5*(10)^2

=60+3/5*100

=60+60

=120 m

Answered by anishka56
6

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120 m.

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