Question

a car accelerates from 6m/s to 16m/s in 10 second. calculate (a) the acceleration (b) the distance covered by car in that time

Answer 1

u = 6m/s

v = 16m/s

t = 10s.

a = v-u/t

a  = 16-6/10

= 10/10

a = 1m/s²

distance =?=s

We know that,

2as = v²-u²

2(1)(s) = (16)²-(6)²

2s = 256-36

2s = 220

s = 110

Answer 2

Acceleration is 1 m/s and distance covered is 110 m.

Given - Velocity and time

Find - Acceleration and distance

Solution - We will use equation of motion to find acceleration and distance covered.

a) Acceleration

v = u + at

at = v - u

a = (v - u)/t

a = (16 - 6)/10

a = 10/10

a = 1 m/s²

b) Distance

v² = u² - 2aS

2aS = v² - u²

S = (v² - u²)/2a

S = (16² - 6²)/2*1

S = (256 - 36)/2

S = 220/2

S = 110 m

Hence, acceleration is 1 m/s² ans distance is 110 m.

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