A car accelerates from 6m/s to 16m/s in 10 seconds. calculate the acceleration and the distance covered by the car in that time
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Answered by
49
This is simple
Acceleration = (Final velocity-initial velocity)/2
Thus a= 16-6/10
=1 m/s^2.
Distance covered is given by the equation s=ut+1/2 at^2
Where u is initial velocity, a is acceleration.
S= 6*10+1/2*1*10^2
=110m.
Cheers. Mark brainliest.
Acceleration = (Final velocity-initial velocity)/2
Thus a= 16-6/10
=1 m/s^2.
Distance covered is given by the equation s=ut+1/2 at^2
Where u is initial velocity, a is acceleration.
S= 6*10+1/2*1*10^2
=110m.
Cheers. Mark brainliest.
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26
find this solution.m.........
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