A car accelerates from 6m/s to 16m/s in 10s.calculate the acceleration and the distance covered by the car in that time
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According to the question,
X = 180°-125° = 55° (Adjacent Angle)
Y+56°=125°
Y = 125°-56° = 69°
If angle BEC is P and
Angle B is equal to X
56° + 55° + P=180° (By Angle Sum Property)
P=169°
Z=180°-169° = 111°
Therefore, answer: - Angle X = = 125°, Angle Y = 69° and Angle Z = 111°
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