Question

A car accelerates from 6m/s to 16m/s in 10sec. Calculate :

(a) the acceleration, and

(b) the distance covered by the car in that time.​

Answer 1

Answer:

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Explanation:

Initial velocity = u

u=6m/s

Final velocity = v

v=16m/s

Time=t=10s

⋅Acceleration=a

a=(v−u)/t

=(16−6)/10

                      →→=1m/s  

2 .Distance=s

From the newton's second law,

s= 2a(v²-u²)  

​s=  (2×1) (256−36)

​ →→ =110m

Answer 2

Answer:

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