A car accelerates from 6ms -1 to 16 ms -1 in 10 seconds. Calculate (a) the acceleration and (b)the distance covered by the car in that time.
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Answer:
u=6m/s
v=16m/s
t=10 seconds
a=v-u/t
a=16-6/10
a=1m/s²
to find the distance....
s=ut+1/2at²
s=6×10+1/2×1×10×10
s=60+50
s=110m
hope it helps....
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