Question

A car accelerates from 6ms-1 to 16ms-1 in 10 sec.Calculate
i) the acceleration and
ii) the disatance covered by the car in that time​

Answer 1

Given:

Initial velocity (u)- 6 m/s

Final velocity (v)-16 m/s

Time (t)- 10 sec

Acceleration (a) -?

Distance (S) = ?

As we know that :-

a =( v - u )/t

=> a = (16 - 6)/10

=> a = 10/10

=> a = 1 m/s^2

S = ut + 1/2a(t)^2

=> S = 6*10 + 1/2*1*(10)^2

=> S = 60 + 1/2*100

=> S = 60 + 50

=> S = 110 m.