Question

a car accelerates from 6ms-1 to 16ms-1 in 10 second. (a) the acceletation and (b) the distance covered by the car in that time​

Answer 1

Answer:

u=6m/s

v=16m/s

t=10 sec

a=(v-u)/1

a=(16-6)/10

a=10/10

a=1m/s^2

s=ut+1/2 at^2

s=6×1+1/2×1×10×10

s=6+100/2

=6+50

distance is 65m if you like then like this answer and say thank you

Answer 2

Answer:

initial velocity =6m/s

final velocity =16m/s

acceleration =a

time =10sec

a= v - u

t

a = 16 -6

10

a = 10

10

a= 1m/sec^2

s= ut+ 1 at^2

2

s = 6 x 10+1 x 1x 100

2

s=60+50

s=110 meters. and.