a car accelerates from 6ms-1 to 16ms in 10seconds. calculate the acceleration and distance covered by car
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u=6m/s
v=16m/s
t=10sec
a=v-u/t
a=16-6/10
a=1m/s^2
v^2-u^2=2as
256-36=2×1×s
220=2s
s=220/2
s=110 m
v=16m/s
t=10sec
a=v-u/t
a=16-6/10
a=1m/s^2
v^2-u^2=2as
256-36=2×1×s
220=2s
s=220/2
s=110 m
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