A car accelerates from 6s/ to 16m/s in 10s.calculate the acceleration.
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hey
here's your answer!!
Initial velocity ( u ) = 6 m / s .
Final velocity ( v ) = 16 m / s .
Time taken ( t ) = 10 s .
Therefore acceleration ( a )
= v - u / t
= ( 16 m / s - 6 m / s ) / 10 s
= ( 10 m / s ) / 10 s
= 1 m / s^2 . (ANSWER)
Hope it helps !!
here's your answer!!
Initial velocity ( u ) = 6 m / s .
Final velocity ( v ) = 16 m / s .
Time taken ( t ) = 10 s .
Therefore acceleration ( a )
= v - u / t
= ( 16 m / s - 6 m / s ) / 10 s
= ( 10 m / s ) / 10 s
= 1 m / s^2 . (ANSWER)
Hope it helps !!
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Answered by
0
initial velocity (u) = 6 m/s
final velocity(v) = 16 m/s
time ( t)= 10seconds
acceleration = v- u/t
= 16-6/10 = 1m/s^2
final velocity(v) = 16 m/s
time ( t)= 10seconds
acceleration = v- u/t
= 16-6/10 = 1m/s^2
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