Question

a car accelerates from rest & acquire a speed of 36km/h in 10seconds find acceleration, total distance travelled , velocity at the end of 6th second, distance travelled in the 6th second​

Answer 1

First, we need to convert 36 km/hr into m/s, i.e, the SI unit.

km/hr * 5/18 = m/s

36 * 5/18 = 10m/s

For acceleration,

v = u + at

10 = 0 + 10a

a = 1m/s² = acceleration

Total distance travelled (s) = ut + 1/2at²

= 0 + 100/2

= 50m

Velocity at the end of the 6th second =

v = u + at

= 0 + (1*6) = 6m/s²

Distance travelled in the 6th second =

s = ut + 1/2at²

= 0 + 36/2

= 18m

Answer 2

Answer:

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