a car accelerates from rest & acquire a speed of 36km/h in 10seconds find acceleration, total distance travelled , velocity at the end of 6th second, distance travelled in the 6th second
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First, we need to convert 36 km/hr into m/s, i.e, the SI unit.
km/hr * 5/18 = m/s
36 * 5/18 = 10m/s
For acceleration,
v = u + at
10 = 0 + 10a
a = 1m/s² = acceleration
Total distance travelled (s) = ut + 1/2at²
= 0 + 100/2
= 50m
Velocity at the end of the 6th second =
v = u + at
= 0 + (1*6) = 6m/s²
Distance travelled in the 6th second =
s = ut + 1/2at²
= 0 + 36/2
= 18m
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