Question

A car accelerates from rest at a constant rate a
for some time after which it decelerates at a constant
rate B to come to rest. If the total time elapsed is
tthen (i) the maximum velocity attained (ii) the total
distances are​

Answer 1

Explanation:

Let maximum velocity=v 

Now,v=0+αt1

Similarly, 0=v−βt2

From the above equations we get,t1=αv&t2=βvt1+t2=t=αv+βv⇒v=α+βαβt

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