a car accelerates from rest at a constant rate alpha for some time, after which it decelerates at a constant rate beeta and comes to rest. if the total time elapsed is t, the maximum velocity acquired by the car will be,t distance covered by car in term of alpha,beta and t
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Let maximum velocity be v
Using v = u + at
v = 0 + α t1
when car deaccelerates initial velocity become v ,
final velocity be zero Using
0 = v - βt2
from both equations , we get
v = αt1 = βt2
total time elapsed is t
t1 + t2 = t
v/α + v/β = t
v( 1/α + 1/β) = t
v[(α+β)/αβ)] = t
maximum velocity attained by car, v = αβt /(α+β)
Using v = u + at
v = 0 + α t1
when car deaccelerates initial velocity become v ,
final velocity be zero Using
0 = v - βt2
from both equations , we get
v = αt1 = βt2
total time elapsed is t
t1 + t2 = t
v/α + v/β = t
v( 1/α + 1/β) = t
v[(α+β)/αβ)] = t
maximum velocity attained by car, v = αβt /(α+β)
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