Question

a car accelerates from rest at a constant rate alpha for some time after which it deccelerates at a at a constant rate beta to come to rest. if the time elasped is the seconds, calculate the maximum velocity reached and the total distance travelled​

Answer 1

Answer:

Explanation:

Let maximum velocity=v  

Now,v=0+αt  

1

​  

 

Similarly, 0=v−βt  

2

​  

 

From the above equations we get,

t  

1

​  

=  

α

v

​  

&t  

2

​  

=  

β

v

​  

 

t  

1

​  

+t  

2

​  

=t=  

α

v

​  

+  

β

v

​  

 

⇒v=  

α+β

αβ

​  

t