Question

A car accelerates from rest at a constant rate \alphaα for some time and after that it decelerates at a constant rate \betaβ, to come to rest. If the total time taken is t, the total distance traveled by the car is

Answer 1

Answer:

ANSWER

Let maximum velocity=v

Now,v=0+αt

1

Similarly, 0=v−βt

2

From the above equations we get,

t

1

=

α

v

&t

2

=

β

v

t

1

+t

2

=t=

α

v

+

β

v

⇒v=

α+β

αβ

t