Question

A car accelerates from rest at a rate of 7.1m/s2 for a time of 3.9s. Calculate the distance it travels at this time.

Answer 1

Answer:

Step-by-step explanation:

1. speed⇒d÷t then u say speed⇒7.1ms⁻²,time⇒3.s ,so u say 7.1⇒d÷3 and is the same as 7.1×3⇒21.3m                                                                                                                                  

Answer 2

Answer:

53.9955 m

Step-by-step explanation:

Initial Velocity (u) = 0 m/s

Acceleration (a) = 7.1 m/s^2

Time (t) = 3.9 seconds

Distance = ?

s= ut + 1/2 * at^2

= 0 * 3.9 + 1/2 * 7.1 * 3.9 * 3.9

= 0 +   1/2 * 7.1 * 3.9 * 3.9

= 107991 / 2000

= 53.9955 m

Hope it helps !!!!