Question

a car accelerates from rest at constant rate 2m/s2 for some time. then it retards at constant rate 4m/s2 and comes to rest. if total time of motion be 3 second. then total distance travelled by car is

Answer 1

Explanation:

in don't no exactly but I know 5m

Answer 2

Answer:

-18m

Explanation:

acceleration of that car = +2$m$/$s^{2}$

retardation                    = - 4$m$/$s^{2}$

total acceleration (vector acceleration) = [+2 - 4 ] $m$/$s^{2}$

                                                                 = -2$m$/$s^{2}$

acceleration × time = Δ velocity

-2$m$/$s^{2}$  × 3$s$  = -6$m/s$

since velocity = -6$m/s$  

velocity × time taken = distance {hint - [ $m/s$ × $s$ = m ] }

-6$m/s$  ×  3$s$ = -18$m$  

∴ the total distance traveled by car = -18$m$