Question

A car accelerates from rest at the constant rate alpha for some time after which it decelerate at a constant rate beta and comes to rest. If total time elapsed is t then maximum velocity acquired by car will be?​

Answer 1

Let "v" represent the maximum speed :

v=u+αt = αt

t = v/αt .....(1)

When deceleration begins :

Slope gives , deceleration .

0=v-β(t'-t)

β = v/t-t'

t-t' = v/β ......(2)

Adding (1) & 2:

v = tαβ/(α+β)

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Answer 2

Answer:

For the first leg of the journey,

V = 0 + α  t1

So  V = α  t1

for the second leg of journey of duration  t - t1 :

0 = V - β (t - t1)

0 = α t1 - β t + β t1

t1 = β t / (α + β)

V =  αt1 = α β t / (α + β )

                                                                                   

HOPE THIS WILL HELP YOU....

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