Question

a car accelerates from rest to 7.1m/second square for time 3.9 second calculate the distance traveled at this time
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Answer 1

Answer:

The equation for problems of this sort is as follows: ... If a car travels a distance of 90 M with a final velocity of 30 M per second from rest ... distance = (((acceleration x time) / 2) x time).

Answer 2

Answer:

54 m

Explanation:

Given :

Initial velocity u = 0 m / sec

Acceleration a = 7.1 m / sec²

Time t = 3.9 sec

We are asked to find distance s :

Using second equation of motion i.e. :

s = u t + 1 / 2 a t²

Putting values here we get :

s = 0 × 3.9 + 1 / 2 × 7.1 × 3.9² m

s = 0 + 3.55 × 3.9² m

s =  3.55 × 15.21 m

s = 53.99 ≈ 54 m

Therefore , distance traveled at this time is ≈ 54 m.