Question

A car accelerates from rest with acceleration 1.2 m s2. A bus moves with constant speed of 12m/s in a parallel lane . how long the car take from its start to meet the bus​

Answer 1

Answer:

17.14 sec

Explanation:

For Car, S = ( 1 / 2 ) x a x t² - Here a = 1.2 m/s²

For Bus, S - v x t - Here v = 12 m/s

Equating both we get,

( 1 / 2 ) x a x t² = v x t

∴ ( 1 / 2 ) x 1.2 x  t² = 12 x t

∴ t = 17.14 sec