Question

a car accelerates of uniform from 36 km per hour to 72 km per hour in 10 seconds The distance covered by the car in metres ​

Answer 1

Answer:

distance=150m

Explanation:

from first equation of motion we find acceleration a=1m/s

u=32km/h

=10m/s

v=72km/h

72×5/18=20m/s

Now,V=U+at

a=v-u/t

a=20-10/10

a=1m/s

And,x=ut+1/2at^2

x=10×10+1/2×1×10^2

x=150m

Answer 2

Answer:

Given: u(Initial Velocity)=36km/h     v(Final Velocity)=72km/h

                                      =36*5/18                                =72*5/18

                                      =10m/s                                   =20m/s

t(time taken)=10 sec    a(accelaration) = 5m/s²

To Find: s ( distance )=?  

Explanation:

Using the 2nd equation of motion,

s=ut+1/2at

s= 10*10+1/2*5*10

s= 100+1/2*50

s= 50+1*50

s=50+50

s = 100 metres

Hope It Helps You !!