Question

A car accelerates uniformly -1 from 18 km h to 36 km h in 5 s.

Calculate (i) the acceleration and (ii) the distance covered by the car in that time.​

Answer 1

Answer:

LET THE INITIAL AND FINAL VELOCITY BE 'U' AND'V' RESPECTIVELY

U=18KM/H=18*5/+8=5M/S

V=36KM/H=36*5/18=10M/ST=5SECONDS 1)

ACCELERATION=V-U/T=10-5/5=1 M/S^2

2)

S=UT+1/2AT^2

=5×5+1/2*1*5*5

=25+25/2

=37.5 METRES

PLZ MARK BRAINLIEST.....

I HAVE SHOWN ALL STEPS....PLZZ

Answer 2

Answer:

LET THE INITIAL AND FINAL VELOCITY BE 'U' AND'V' RESPECTIVELY

U=18KM/H=18*5/+8=5M/S

V=36KM/H=36*5/18=10M/ST=5SECONDS 1)

ACCELERATION=V-U/T=10-5/5=1 M/S^2

2)

S=UT+1/2AT^2

=5×5+1/2*1*5*5

=25+25/2

=37.5 METRES

PLZ MARK BRAINLIEST.....

@vidush