Question

A car accelerates uniformly 18km/hr in 5s. calculate acceleration of car.​

Answer 1

$\huge\underline\bold{Solution}$ :-

We are given that :-

u = $18km\:{h}^{-1}$ = $5m\:{s}^{-1}$

v = $36km\:{h}^{-1}$ = $10m\:{s}^{-1}$

t = $5s$

$\huge\underline\bold{We\:have}$ :-

$\huge\boxed{a\:=\: \dfrac{v-u}{t}}$

$\hookrightarrow\: \dfrac{10m\:{s}^{-1}\:-\:5m\:{s}^{-1}}{5s}$

$\hookrightarrow\:1m\:{s}^{-2}$

$\huge\underline\bold{We\:have}$ :-

$\huge\boxed{s\:=\:ut\: \dfrac{1}{2}{at}^{2}}$

$\hookrightarrow\:5m\:{s}^{-1}\:×5s\:+ \dfrac{1}{2}\:×\:1m\:{s}^{-2}\:×\:{(5s)}{^2}$

$\hookrightarrow\:25m\:+12.5m$

$\hookrightarrow\:37.5m$

The acceleration of the car is $1m\:{s}^{-2}$ and the distance covered is 37.5 m.

Answer 2

Answer:

Solution

:-

We are given that :-

u = 18km\:{h}^{-1}18kmh

−1

= 5m\:{s}^{-1}5ms

−1

v = 36km\:{h}^{-1}36kmh

−1

= 10m\:{s}^{-1}10ms

−1

t = 5s5s

\huge\underline\bold{We\:have}

Wehave

:-

\huge\boxed{a\:=\: \dfrac{v-u}{t}}

a=

t

v−u

\hookrightarrow\: \dfrac{10m\:{s}^{-1}\:-\:5m\:{s}^{-1}}{5s}↪

5s

10ms

−1

−5ms

−1

\hookrightarrow\:1m\:{s}^{-2}↪1ms

−2

\huge\underline\bold{We\:have}

Wehave

:-

\huge\boxed{s\:=\:ut\: \dfrac{1}{2}{at}^{2}}

s=ut

2

1

at

2

\hookrightarrow\:5m\:{s}^{-1}\:×5s\:+ \dfrac{1}{2}\:×\:1m\:{s}^{-2}\:×\:{(5s)}{^2}↪5ms

−1

×5s+

2

1

×1ms

−2

×(5s)

2

\hookrightarrow\:25m\:+12.5m↪25m+12.5m

\hookrightarrow\:37.5m↪37.5m

The acceleration of the car is 1m\:{s}^{-2}1ms

−2

and the distance covered is 37.5 m.