Question

a car accelerates uniformly 36 km/h to 72km/h in 5 seconds the acceralation is?

Answer 1

Answer:

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Explanation:

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Answer 2

Given Information :

• Initial velocity (u) = 36 km/h

• Final velocity (v) = 72 km/h

• Time taken (t) = 5 s

To calculate :

• Acceleration (a)

Conversion of units :

We'll be calculating the value of acceleration in its SI unit, that is m/s². So, we need to convert the velocities in m/s.

• In order to convert km/h to m/s, we multiply the give value with 5/18.

Converting initial velocity (u) into m/s :

→ 36 km/h = 36 × $\sf \dfrac{5}{18}$ m/s

→ 36 km/h = 2 × 5 m/s

→ 36 km/h = 10 m/s

Converting final velocity (v) into m/s :

→ 72 km/h = 72 × $\sf \dfrac{5}{18}$ m/s

→ 72 km/h = 4 × 5 m/s

→ 72 km/h = 20 m/s

Calculations :

As we know that,

• Acceleration is defined as rate of change in velocity with time, so

$\boxed { \sf {Acceleration = \dfrac{v-u}{t}} }$

• v denotes final velocity.
• u denotes initial velocity.
• t denotes time.

Substituting values,

$\longmapsto \sf {a = \dfrac{20-10}{5} }$

$\longmapsto \sf {a = \dfrac{10}{5} }$

$\longmapsto \boxed{\sf\red {a = 2 } }$

Therefore, acceleration is 2 m/s².

Points to remember :

• Acceleration is defined as rate of change in velocity with time.

• $\boxed { \sf {Acceleration = \dfrac{Change \:in \: velocity}{Time}} }$

• SI unit of acceleration is m/s².

• Negative acceleration is known as retardation.