Question

A car accelerates uniformly at the rate of 2m/s after starting from rest. Find the distance traveled and the velocity attained in 4 sec

Answer 1

Answer:

16 m and 8 m/s

Explanation:

According to the given question,

a = acceleration = 2 m/s^2

u = initial velocity = 0 m/s

t = time = 4 s

v = final velocity and s = displacement

And we are asked to find distance.

Here distance is equal to displacement as it's linear motion.

We know,

• v = u+at

Putting the values we get,

• v = 0+2×4

• v = 8 m/s

Thus final velocity after 4 sec is 8 m/s with acceleration of 2 m/s^2.

Again,

• s = ut+1/2 at^2

Putting the values we get,

• s = 0+ 1/2×2×16

• s = 16 m

Thus distance is 16 m when acceleration is 2 m/s^2 and time is 4 sec.

Answer 2

Answer:

$\large{\underline{\boxed{\sf Distance = 16 \: m}}}$

$\large{\underline{\boxed{\sf Velocity = 8 \: m/s}}}$

Explanation:

Given that ;

Acceleration of car (a) = 2 m/s²

Initial velocity of car (u) = 0 m/s

Time taken (t) = 4 secs

To find: The distance travelled by car and the velocity attained.

Solution:

We will use first equation of motion;

v = u + at

⇒ v = 0 + 2 * 4

⇒ v = 8 m/s

Thus, the final velocity of car is 8 m/s.

_______________________

Now, using second equation of motion;

$\sf s = ut + \frac{1}{2} \: {at}^{2} \\ \\ \implies \sf s =0 * 4 + \frac{1}{2} * 2 * 4 * 4 \\ \\ \implies \sf s =0 + 16 \\ \\ \implies \sf s =16 \: m$

Hence, the distance travelled by car is 20 m.