Question

a car accelerates uniformly by 1m/s² from 5 to 10m/s in 5s calculate distance covered by the car in that time
correct answer plz​

Answer 1

Answer:

Distance covered by car is 37.5m

Explanation:

By 2nd equation of motion

s=ut+1/2at?

s=5(5)+1/2(1)(5)2

s=25+25/2

s=25+12.5

s=37.5m

Answer 2

Given-

• Acceleration, a = 1 m/s²
• initial velocity, u = 5m/s
• final velocity, v = 10 m/s
• time period,t = 5s

To Find-

• Distance travelled by car in given time period

Solution-

We know

$\boxed{ v^2 - u^2 = 2aS }$

where S = distance

$\implies\;S = \frac{v^2 - u^2}{2a}$

$S =\dfrac{ 10^2-5^2}{2\times 1}</p><p>\quad\quad\quad\quad(Putting\:Values)$

$S = \dfrac{100-25} {2}$

$S = \dfrac{75}{2}$

$S = 37.5 \;m$

$\boxed{\textsf{Distance covered by the car in that time= 37.5 m}}$