Question

A car accelerates uniformly by 1m/s² from 5m/s to 10m/s in 5s. Calculate
covered by the car in that time.
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Answer 1

Answer:

Distance covered by car is 37.5m

Explanation:

By 2nd equation of motion

s=ut+1/2at²

s=5(5)+1/2(1)(5)²

s=25+25/2

s=25+12.5

s=37.5m

Alternative Solution

By 3rd equation of motion

v²-u²=2as

(10)²-(5)²=2(1)s

100-25=2s

75=2s

s=75/2m

s=37.5m

Answer 2

✬ Distance = 37.5 m ✬

Explanation:

Given:

• Acceleration of car is 1 m/s².
• Initial velocity of car is 5 m/s.
• Final velocity is 10 m/s.
• Time taken by car is 5 seconds.

To Find:

• Distance covered by car in that time ?

Formula to be used:

• s = ut + 1/2at² (Third law of motion)

Solution: Here we have

• u = 5 m/s.
• v = 10 m/s.
• t = 5 s
• a = 1 m/s²
• s = ?

Put all the values on the formula.

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ 5 × 5 + 1/2 × 1 × 5²

$\implies{\rm }$ 25 + 1/2 × 5 × 5

$\implies{\rm }$ 25 + 1/2 × 25

$\implies{\rm }$ 25 + 25/2

$\implies{\rm }$ 25 + 12.5

$\implies{\rm }$ 37.5

Distance covered by car is 37.5 m.

Lest find it through another method.

Formula to be used:

• v² = u² + 2as (third law of motion)

Solution: Put all the values on formula

$\implies{\rm }$ v² = u² + 2as

$\implies{\rm }$ 10² = 5² + 2 × 1 × s

$\implies{\rm }$ 10 × 10 = 5 × 5 + 2s

$\implies{\rm }$ 100 = 25 + 2s

$\implies{\rm }$ 100 – 25 = 2s

$\implies{\rm }$ 75/2 = s

$\implies{\rm }$ 37.5 = s

Distance covered by car is 37.5 m.