A car accelerates uniformly from 0.00km per hour to 54 km per hour in 6mintes. calculate the acceleration and distance.
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u=0
v=15 m/s
acceleration=(v-u)/t
=(15-0)/360
=15/360
=0.041666666
distance= speed×time
first we have to take average speed.
=15+0/2
=7.5 m/s
now,
7.5×360
=2700m
v=15 m/s
acceleration=(v-u)/t
=(15-0)/360
=15/360
=0.041666666
distance= speed×time
first we have to take average speed.
=15+0/2
=7.5 m/s
now,
7.5×360
=2700m
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