Question

A car accelerates uniformly from 10 ms-1

to 20 ms-1

in 2 seconds. Calculate the acceleration and the

distance covered by the car in that time.​

Answer 1

Answer:

car starts form rest and accelerates uniformly for 10s to a velocity of 8ms-1. It then runs at a constant velocity an dis finally brought to rest in 64m with a constant retardation. The totla distance covered by the car is 584m Find the value of acceleration, retardation, and totl time taken.

Answer 2

Answer: hope this ans helps you....Pls mark me as brainliest

Explanation:

initial velocity, u =10m/s

final velocity, v=20m/s

time, t=2s

acceleration, a = v-u/t

= 20-10/2=10/2=5m/s^2

distance, s=ut+1/2 at^2

10*2+1/2*5*2^2=  20+1/2*5*4

= 20+5*2=20+10=30m

therefore s, distance =30m..