Question

A car accelerates uniformly from 108 km/h to 126 km/h in 5 s.Calculate
(i) the acceleration and
(ii) the distance covered by the car in that time. ​

Answer 1

Answer:

i) 1 m/ s²

ii). 162.5 m

Explanation:

i)108 km/h = 30m/ s. ( multiply by 5/18)

126 km/h= 35m/s ( multiply by 5/18)

v= u+ at

35 = 30 + a×5

35-30=5a

5/5=a

1m/ s²=a

ii) let the distance covered be S

so, v²=u²+2aS

35²=30²+2×1×S

1225-900=2S

325/2=S

162.5m=S

Answer 2

Answer:

Explanation:

initial velocity  = 108km/h

final velocity = 126km/h

acceleration =

v= u+at

126 = 108+ a5

5a = 126-108

5a = 18

a = 18/5 km /h^1