a car accelerates uniformly from 118 km\h to 154 km\h in 6s find the acceleration and then find the distance travelled by the time
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Acceleration=v-u/t
=385/9-295/9/6
=90/9/6
=10/6m/s2
distance traveled=ut+1/2at2
=295/9*6+1/2*10/6*6*6
=295/3*2+5*6
=590/3+30
=(590+90 )/3
=680/3m
=385/9-295/9/6
=90/9/6
=10/6m/s2
distance traveled=ut+1/2at2
=295/9*6+1/2*10/6*6*6
=295/3*2+5*6
=590/3+30
=(590+90 )/3
=680/3m
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