Question

A car accelerates uniformly from 15m/s to 20m/s in 10 seconds. Calculate the distance covered by the car during this time interval.​

Answer 1

Given :-

☄ Initial velocity, u = 15 m/s

☄ Final velocity, v = 20 m/s

☄ time taken, t = 10 s

To find :-

Distance travelled by bus during this time interval

Solution :-

Using the first equation of motion .i.e.,

➠ v = u + at

➠ 20 = 15 + (a)(10)

➠ 20 - 15 = 10a

➠ 5 = 10a

➠ a = 5/10

➠ a = 0.5 m/s²

now,

Using the second equation of motion .i.e.,

➠ s = ut + 1/2 at²

➠ s = (15)(10) + 1/2 (0.5)(10)²

➠ s = 150 + 25

➠ s = 175 m

thus, the distance covered by the car during that time interval is 175m.

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