A car accelerates uniformly from 18.5m/s to 46.1m/s in 2.47seconds. determine the acceleration of the car and distance travelled by the car
Answers
Answered by
2
a=v-u/t
a=46.1-18.5/2.47
a=36.610m/s square
a=46.1-18.5/2.47
a=36.610m/s square
Answered by
1
v=46.1m/s
u=18.5m/s
t=2.47 s
v=u+at
46.1=18.5+a2.47
46.1-18.5=2.47a
33.6=2.47a
a=33.6/2.47
a=13.06m/s²
s=ut+1/2at²
s=18.5(2.47)+1/2(13.06)(2.47)²
s=85.5 m
plz Mark as brainlist answer
u=18.5m/s
t=2.47 s
v=u+at
46.1=18.5+a2.47
46.1-18.5=2.47a
33.6=2.47a
a=33.6/2.47
a=13.06m/s²
s=ut+1/2at²
s=18.5(2.47)+1/2(13.06)(2.47)²
s=85.5 m
plz Mark as brainlist answer
Similar questions