Question

A car accelerates uniformly from 18 kilometre per hour to 36 km per hour in 5 minutes Find the acceleration​

Answer 1

Explanation:

So, 18 × 5/18 = 5 m/s. Similarly, the final velocity is given as 36 km/s. So, 36 × 5/18 = 10 m/s

Answer 2

Correct question :

A car accelerates uniformly from 18km per hour to 36km per hour in 5 seconds . Calculate the acceleration and the distance covered by the car in time.

GiveN that,

• Time taken, t = 5 sec

• Initial velocity,

↬ u = 18 km/hour

↬ u = 18 × 1000/60 × 60

↬ u = 5 m/s

• Final velocity,

↬ v = 36 km/hr

↬ v = 36 × 1000/ 60 × 60

↬ v = 10 m/s

As per the question, we've to find out the acceleration and distance travelled.

So, we know that,

$\longrightarrow\sf Acceleration = \dfrac{(v - u)}{t}$

Substituting the values,

$\longrightarrow\sf a = \dfrac{(10 - 5)}{5}$

$\longrightarrow\sf a = \dfrac{5}{5}$

$\longrightarrow\large \sf { \boxed{ \sf{a = 1 m/s^2}}}$

Now,

We know the required formula to calculate distance travelled,

We can use the third equation of motion :

$\longrightarrow\sf S = u t + \dfrac{1}{2}at^2$

Substituting the given values in the above equation we get,

$\longrightarrow\sf S = 5 \times 5 + \dfrac{1}{2} \times 1 \times 5^2$

$\longrightarrow\sf S = 25 + \dfrac{1}{2} \times 25$

$\longrightarrow\sf S = 25 + 12.5$

$\longrightarrow \large{ \boxed{\sf S = 37.5 \ m}}$

$\therefore$ Acceleration & distance travelled is 1 m/s² & 37.5 m respectively.