A car accelerates uniformly from 18 kilometre per hour to 36 km per hour in 5 seconds calculate acceleration and distance covered by the car in that time
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Answered by
26
the correct answer is
u =18km/hr=18×5/18
=5m/s
v=36km/hr =36×5/18
=10m/s
t=5sec
a= ?
a= v-u/t
a=10-5/5
=5/5
=1m/s2
d=?
v2-u2=2as
v2-u2/2a=s
100-25/2=s
37.5m)=s
hope it helps
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Answered by
9
Here is your answer
V = final velocity
U= initial velocity
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