Question

A car accelerates uniformly from 18 km h–1 to 36 km h–1 in 10 s. Calculate (i) the acceleration and (ii) the distance covered by the car in that time.

Please answer fast!!!! ​

Answer 1

Answer:

Using Newton's 1st Law of Motion,

v = u + at

36 = 18 + a × 10

36 - 18 = 10a

18 = 10a

a = 1.8 m/sec.^2

Using Newton's 3rd Law of Motion,

v^2 - u^2 = 2as

(36)^2 - (18)^2 = 2 × 1.8 × s

1296 - 324 = 2 × 1.8 × s

972 = 2 × 1.8 × s

s = 972 / 2 × 1.8

s = 972 × 10 / 2 × 18

s = 27 × 10

s = 270 m

Therefore, the acceleration is 1.8 m/sec.^2 & distance covered during this time is 270 m.

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