A car accelerates uniformly from 18 km h–1 to 36 km h–1 in 5 s. Calculate (i) the acceleration and (ii) the distance covered by the car in that time.
NCERT Class IX
Sciences - Main Course Book
Chapter 8. Motion
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u = 18 kmph
v = 36 kmph
t = 5 sec
a = (v - u) / t = (36-18)/5 = 3.6 m/sec/sec
s = (v + u)/2 * t = (18+36)/2 * 5 = 135 meters
v = 36 kmph
t = 5 sec
a = (v - u) / t = (36-18)/5 = 3.6 m/sec/sec
s = (v + u)/2 * t = (18+36)/2 * 5 = 135 meters
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