Question

A Car accelerates uniformly from 18 km h-1 to 36km h-1 in 5 s. Calculate (i) the acceleration and ( ii ) the accelerations covered by the car in that time . ​

Answer 1

Answer:

Hence, the acceleration of the car is 1 m/s². ⇒ s = 37.5 m. Hence, the distance covered by car is 37.5 m.

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Answer 2

Answer:

Given that,

u=18km/hr=18×5/18=5m/s

V=36km/hr=36×5/18=10m/s

Time, t =5 sec

From the first law of motion,

V=u+at

a=v-u/t

a=5/5=1m/s²

2) From the third law of motion,

V²-u²=2as

100-25=2s

2s=75

S=37.5m

Explanation:

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