Question

A car accelerates uniformly from 18 km h–1to 36 km h–1in 5 s. Calculate
(i) the acceleration and
(ii) the distance covered by the car in that time.

Ncert class 9th Physics chapter Motion
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Answer 1

37.5

Explanation:

Acceleration = Change in Velocity/Time

Change in Velocity = 36-18 = 18 km/h=5 m/s

Time= 5 Seconds

Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2

u=18 km/h=5 m/s

t=5 s

a=1 m/s2

s= (5*5)+(1/2*1*5*5)

s=25+12.5 i.e., s=37.5 m

Hence,the dustance covered by the car is 37.5

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