a car accelerates uniformly from 18 km/h to 36 km/h in 2 seconds.calulate the distance covered by the car in that time.
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given:-
u =18km/h-------m/sec
18×5/18=5 m/sec
v=36km/h-----m/sec
36×5/18=10m/sec
time=2
acceleration =v-u/t
a=10-5/2=5/2=2.5m/sec2
given:-
u =18km/h-------m/sec
18×5/18=5 m/sec
v=36km/h-----m/sec
36×5/18=10m/sec
time=2
acceleration =v-u/t
a=10-5/2=5/2=2.5m/sec2
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